Asystem consists of two particles. at t = 0 one particle is at the origin; the other, which has a mass of 0.50 kg, is on the y-axis at y = 6.0 m. at t = 0 the center of mass of the system is on the y-axis at y = 2.4 m. the velocity of the center of mass is given by (0.75 m/s3) t2i^. a)find the total mass of the system b)find the acceleration of the center of mass at any time t. c)find the net external force acting on the system at t = 3.0 s

Explanation:

It is given that,

Initial location of particle 1, y₁ = 0

Mass of other object, m₂ = 0.5 kg

Location of particle 2, y₂ = 6 m

The center of mass of the whole system, Y = 2.4 m

(a) At t = 0 the center of mass of the system is on the y-axis at y = 2.4 m. Let m₁ is the mass of first mass. Using the formula of the center of mass as :

(b) The velocity of the center of mass is given by :

Let a is the acceleration of the center of mass. The derivative of velocity is called acceleration.

(c) Let F is the net force acting on the system. It is given by :

a at t = 3 s,

Hence, this is the required solution.

divide the right side by the left side

0.024÷1.2=0.02 for example

where is the circuit diagram ?