When a mass of 35 g is attached to a certain spring, it makes 30 complete vibrations in 5.0 s. what is the spring constant of the spring?

50 N/m

Explanation:

The period is:

T = 5.0 s / 30

T = 0.167 s

The frequency is:

f = 1 / T

f = 6.0 Hz

The angular frequency is:

ω = 2πf

ω = 37.7 rad/s

Finding the spring constant:

ω = √(k / m)

k = ω² m

k = (37.7 rad/s)² (0.035 kg)

k = 49.7 N/m

Rounding, the spring constant is 50 N/m.

we need answer choices

double the distance = divide strength by 4