An olympic discus thrower (~100 kg) launches the 2.0 kg discus by spinning rapidly (~4 times per second) with arm outstretched (~1.0 meter) just before releasing it. a. how much centripetal force must the athlete provide to keep the discus traveling in a circular path?

F = 1263.03 N

Explanation:s

given,                      

mass of the disk thrower = 100 Kg

mass of the disk = 2 Kg                

angular speed of the disk  = 4 rev/s

arm outstretched = 1 m                  

centripetal force of the disk in the circular path

F = m ω² r                        

ω = 4 x 2 x π        

ω = 25.13 rad/s

F = m ω² r                      

F = 2 x 25.13² x 1

F = 1263.03 N                                              

hence, centripetal force equal to the F = 1263.03 N

i think it’s a. this is because if they measured the mass of something with a mass of 150g, then their final answer would have to be approximately 150g. though all of their answers are almost 150, rosa and tran have the closest answers (or the exact answer) to the accurate one.