At 10: 30 am, detectives discover a dead body in a room and measure its temperature at 27°c. one hour later, the body's temperature had dropped to 24.8°c. determine the time of death (when the body temperature was a normal 37°c), assuming that the temperature in the room was held constant at 22°c. (round your answer to two decimal places.)

: the time of death was hours before 10: 30 am.

The time of death was approximately 4 hours before 10:30 AM.

Explanation:

Temperature of the body when discovered by detective at 10:30 AM= 27°C

After discovery, Temperature of the body at 11.30 AM= 24.8°C

Change in time = ΔT = 1 hour

Rate of change of body temperature with respect to time :

Normal body temperature = 37°C

Change in time since death = ΔT'

The time of death was approximately 4 hours before 10:30 AM.

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s