Aman drags a 8.10 kg bag of mulch at a constant speed, applying a 29.5 n at 38°. what is the coefficient of friction?

The coefficient of friction is 0.38.

Explanation:

The free body diagram is drawn below.

Let be frictional force acting in the backward direction as shown. Let the coefficient of friction be . Let be the normal reaction force acting on the bag.

Given:

Mass of the bag is,

Force acting at ° is

Acceleration due to gravity is,

The force F can be resolved into its components as and

Therefore,

Now, as there is no acceleration in vertical direction, therefore,

Sum of upward forces = Sum of downward forces

Now, as the bag is moving at a constant speed, so acceleration in the horizontal direction is also zero as acceleration is the rate of change of velocity.

Therefore, backward force = forward force.

Now, frictional force is given as:

Therefore, the coefficient of friction is 0.38.

a=d/t

a="triangle"v/t

explanation:

a = acceleration