Before colliding, the momentum of block a is -100 kg*m/, and block b is -150 kg*m/s. after, block a has a momentum -200 kg*m/s. what is the momentum of block b afterward?

The momentum of block B = -50 Kg m/s

Explanation:

Given,

The initial momentum of block A, MU = -100 Kg m/s

The final momentum of block A, MV = -200 Kg m/s

Consider the block B is initially at rest.

Therefore, the initial momentum of block B, mu = -150  Kg m/s

According to the laws of conservation of linear momentum, the momentum of the body before impact is equal to the momentum of the body after impact.

                                MU + mu = MV + mv

                                -100  +  (-150) = (-200) + mv

                                         mv = -250 - 200

                                             =  -50 Kg m/s

Hence, the momentum of the block B after impact is, mv = -50 Kg m/s

no. dot product   =0 when vecs at right angles

when heated, the valance electrons increased their speed and transferred the heat from electron to electron.   i just took the test.