A1.00 kg solid, uniform disk rolls without slipping across a level surface, translating at 3.00 m/s. if the disk's radius is 0.390 m, find the following. (a) the disk's translational kinetic energy (in j) (b) the disk's rotational kinetic energy (in j)

Explanation:

Given that,

Mass of the disk, m = 1 kg

Translational speed of the disk, v = 3 m/s

Radius of the disk, r = 0.39 m

(a) Let K is the tranlational kinetic energy of the disk. Its formula is given by :

K = 4.5 J

(b) Let K' is the rotational kinetic energy of the disk. Its formula is given by :

K' = 2.25 J

Hence, this is the required solution.

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.

it has to be b, about 97 percent.