Assume that the system has zero gravitational potential energy at the lowest point of the motion. derive an expression for the total mechanical energy, eequilibrium, of the system as the monkey passes through the equilibrium position in terms of m, x, d, g, k, and the speed of the monkey, ve

See explanation

Explanation:

From what I can see in the question, there is a monkey of mass m suspened at the end of a spring which constant is k and this monkey has moved a distance d.

The mechanical energy for the situation will be composed of elastic potential energy from the spring, kinetic energy from the monkey and potential gravitational energy from the monkey as well.

where m is the monkey's mass, is the speed of the monkey, d is the distance that the monkey has moved, k is the spring constant and x is the distance that the spring has stretched

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.

i think the answer is a and b

i wish you luck