An irregularly-shaped object of length 9.2 m is placed with each end on a scale. if the scale on the right reads 73 n and the one on the left reads 91 n , how far from the left is the object's center of gravity?

5.1 m

Explanation:

from the question we are given the following:

length of the object (L) = 9.2 m

weight on the right scale (Wr) = 73 N

weight on the left scale (Wl) = 91 N

position of the center of gravity (CG) from the left = ?

We can get the position of the center of gravity (CG) by finding the net torque about the center of gravity (CG).

Take note of the following:

therefore taking the clockwise direction as positive the equation for the net torque about the center of gravity (CG) will be

(Wr x P) - (Wl x (9.2 - P)) = 0

(Wr x P) = (Wl x (9.2 - P))

P =

P =

P= 4.1 m

Recall that the distance of the center of gravity (CG) from the left end is the total length - P = 9.2 - P

= 9.2 - 4.1 = 5.1 m

answer; (arch); good luck