In a physics lab, asha is given a 10.5 kg uniform rectangular plate with edge lengths 66.3cm by 52.1cm . her lab instructor requires her to rotate the plate about an axis perpendicular to its plane and passing through one of its corners, and then prepare a report on the project. for her report, asha needs the plate's moment of inertia with respect to given rotation axis. calculate .

The plate's moment of inertia is 2.489 kg * m²

Explanation:

Step 1: Data given

mass of the uniform rectangular plate = 10.5 kg

lengths of the plate = 66.3cm by 52.1cm

Step 2: Calculate moment of inertia

For an axis through the center of the rectangle, I = m[(w²+L²)/12

Using the parallel axis theorem, the added value of I = mR² = m[(w²/4 + L²/4]

IF we get both reactions together we get:

I = (m/3)*(w²+L²)

I = 10.5/3 *(0.663² + 0.521²)

I = 2.489 kg * m²

The plate's moment of inertia is 2.489 kg * m²

false

explanation:

boats, things on boats luggage are way more heavy then water.

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂