Adelivery truck leaves a warehouse and travels 3.20 km east. the truck makes a right turn and travels 2.45 km south to arrive at its destination. what is the magnitude and direction of the truck’s displacement from the warehouse? group of answer choices 5.65 km, 52.5° south of east 2.40 km, 45.0° south of east 0.75 km, 37.8° south of east 2.30 km, 52.5° south of east 4.03 km, 37.4° south of east

Explanation:

It is given that,

Displacement of the delivery truck, (due east)

Then the truck moves, (due south)

Let d is the magnitude of the truck’s displacement from the warehouse. The net displacement is given by :

d = 4.03 km

Let is the direction of the truck’s displacement from the warehouse from south of east.

So, the magnitude and direction of the truck’s displacement from the warehouse is 4.03 km, 37.4° south of east.

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .