The planet mercury travels in an elliptical orbit with eccentricity 0.206. its minimum distance from the sun is 4.6 ⨯ 107 km. find its maximum distance from the sun. (if you enter your answer in scientific notation, round the decimal value to two decimal places. use equivalent rounding if you do not enter your answer in scientific notation.)

Explanation:

It is given that,

The planet Mercury travels in an elliptical orbit with eccentricity 0.206, e = 0.206

The minimum distance from the sun,

The relation between the minimum and the maximum distance from the sun is given by :

a is the maximum distance from the sun

or

So, the maximum distance from the sun is . Hence, this is the required solution.

the current is 0.6

voltage ÷ resistance = current

so 12 ÷ 20 = 0.6

float.

archimedes' principle

denser than water sinks in water.

denser than mercury would sink in it