Aboat with a horizontal tow rope pulls a water skier. she skis off to the side, so the rope makes an angle of 12.0 ∘ with the forward direction of motion. for related problem-solving tips and strategies, you may want to view a video tutor solution of pushing a stalled car. part a if the tension in the rope is 200 n, how much work does the rope do on the skier during a forward displacement of 320 m?

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j