A2.80 kg mass is dropped from a height of 4.50 m. find its potential energy(pe) when it is 3.00 m above the ground.

82.3 J

Explanation:

PE = mgh

PE = (2.80 kg) (9.8 m/s²) (3.00 m)

PE = 82.3 J

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

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