In february 1955, a paratrooper fell 380 m from an airplane without being able to open his chute but happened to land in snow, suffering only minor injuries. assume that his speed at impact was 54 m/s (terminal speed), that his mass (including gear) was 81 kg, and that the force on him from the snow was at the survivable limit of 1.2 ✕ 105 n.

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j