A2000 kg car is driving on a flat road around a turn with a 50 meter radius of curvature. when the road is dry, the car can go around the turn at a maximum speed of 20 m/s without slipping. what is the coefficient of friction between the road and the tires? is this the coefficient for static or kinetic friction?

μ =0.8

This is the  coefficient for  kinetic friction

Explanation:

Given that

m = 2000 kg

r= 50 m

v= 20 m/s

When a car moves around a circular arc the it experience a radial force F

F= m v²/r

To avoid the slipping friction force must be equal to F

Friction force Fr= μ m g

Fr= F

μ m g= m v²/r

μ =  v²/rg

By putting the values

   ( take g =10 m/s²)

μ =0.8

This is the  coefficient for  kinetic friction

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.