6. a wooden chair is pushed across a wooden floor. the friction force is 34.5 n. what
is the weight of the chair? what is the mass of the chair? (=0.30)
7. a copper piggy bank is pushed across a steel counter. the frictional force is 12 n
what is the mass of the piggy bank? (u= 0.36)
8. you are dragging a cat by its tail. the u between your cat and the floor is 0.21. if the
frictional force between your cat and the floor is 2.5 n, find the cat's mass.
i

6) m = 11.73 Kg

7) m = 3.4 Kg

8) m = 1.21 Kg

Explanation:

6) Given,

The friction force, f = 34.5 N

The coefficient of friction, μ = 0.30

The friction force is given by the formula,

                             f = μ · η

Where η is the normal force acting on the body

                             η = m x g

Substituting 'η' in the above equation

                              f = μ · m x g

                              m = f / μg

Substituting the given values in the above equation

                              m = 34.5 / (0.3 x 9.8)

                                  = 11.73 Kg

Hence, the mass of the wooden chair, m = 11.73 Kg

2) Given,

The friction force, f = 12 N

The coefficient of friction, μ = 0.36

Substituting the given values

                           m = 12 / (0.36 x 9.8)

                               = 3.4 Kg

Hence, the mass of the piggy bank, m = 3.4 Kg

3) Given,

The friction force, f = 2.5 N

The coefficient of friction, μ = 0.21

Substituting the given values

                           m = 2.5 / (0.21 x 9.8)

                               = 1.21 Kg

Hence, the mass of the cat, m = 1.21 Kg

answer: d. objects on jupiter experience more gravity due to more gases