Arrange the fatty acids from highest melting point to lowest melting point.

Answer and Explanation::

Unsaturated fatty acids:

Palmitoleic acid: -0.5 °C

Oleic acid: 13.4 °C

Linoleic acid: -3 °C

Linolenic acid: -11 °C

Arachidonic acid: -49.5 °C

Saturated fatty acids:

Lauric acid: 44.2 °C

Myristic acid: 54 °C

Palmitic acid: 63 °C

Stearic acid: 69.6 °C

Arachidic acid: 76.5 °C

Lignoceric acid: 86 °C

From highest melting point to lowest melting point:

Lignoceric acid

Arachidic acid

Stearic acid

Palmitic acid

Myristic acid

Lauric acid

Oleic acid

Palmitoleic acid

Linoleic acid

Linolenic acid

Arachidonic acid

The arrangement of the fatty acid from the highest melting point to the lowest melting point is ordered as follows;

This question contains a missing image of the list of fatty acids to be ordered and the missing image can be seen in the image attached below.

The melting point of fatty acid largely depends on:

The larger the size of the chain, the more the melting point increases which varies proportionally to the size of the chain.

Also saturated fatty acid(single straight-chain fatty acid) has a higher melting point than an unsaturated fatty acid (fatty acid-containing double bond).

Therefore, the order of the melting point of fatty acid from highest to lowest is:

Learn more about fatty acids here:

link

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.