A29 kg box rests on the back of a truck. the coefficient of static friction between the box and the truck bed is 0.234. the acceleration of gravity is 9.81 m/s 2 . what maximum acceleration can the truck have before the box slides backward?

maximum acceleration will be        

Explanation:

We have given that mass of the box m = 29 kg

Coefficient of static friction

Acceleration due to gravity

For maximum acceleration

So acceleration will be

So maximum acceleration will be

6/12=1/2

step-by-step explanation:

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.