Water from a stationary nozzle impinges on a moving vane with turning angle θ = 120°. the vane moves away from the nozzle with constant speed, u = 10 m/s, and receives a jet that leaves the nozzle with speed v = 30 m/s. the nozzle has an exit area of 0: 004 m^2.
find the force that must be applied to maintain the vane speed constant.

This is the answer of your question

Initial velocity,  u = 4.9 m/sfinal velocity = v m/sinitial height,  h₁ =  245 m    final height, h₂ = 0a = -9.8  m/s²time taken = t secondss = ut + 0.5at²⇒  (h₂-h₁) = ut + 0.5at²⇒  0-245 = 4.9t + 0.5×(-9.8)×t²⇒ -245 = 4.9t - 4.9t²⇒ 4.9t² -4.9t -245 =0solving it, we get   t = 7.59sv  = u +  at = 4.9 -9.8×7.59 = 4.9 - 74.38 = -69.48 m/svelocity is  69.48 m/s downward