Factors that influence diffusion iii carbon is allowed to diffuse through a steel plate 13-mm thick. the concentrations of carbon at the two faces are 0.702 and 0.110 kg of carbon per m³ of iron, which are maintained constant. if the preexponential and activation energy are 6.5 x 10^-⁷ m²/s and 82 kj/mol, respectively, calculate the temperature (in k) at which the diffusion flux is 3.2 x 10-⁹ kg/(m²-s).

Explanation:

We need to use Fick's Law to resolve this problem.

We know for this Law that:

And we know as well that the diffusivity coefficient can be expressed as follows,

Where J is the flux of atoms, D is the diffusivity, R is the gas constant, Ed is the activation energy and \frac{\Delta c}{\Delta x} is the concentration of gradient.

To calculate the temperature we need to remplace the equation of diffusivity coefficient in the Fick's law equation.

Rearrange the equation to get the value of temperature

We have all the values,

So  substituting,

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft