Astring pulls a 9 kg box horizontally across a table with a force of 50 n. the box has a coefficient of friction with the table of 0.45. what is the net force of the box?

a. 90 n
b. 40 n
c. 50 n
d. 10 n

D. 10 N

Explanation:

Draw a free body diagram of the box.  There are four forces:

Normal force N pushing up.

Weight force mg pulling down.

Applied force P to the right.

Friction force Nμ to the left.

Sum of forces in the y direction:

∑F = ma

N − mg = 0

N = mg

Sum of forces in the x direction:

∑F = P − Nμ

∑F = P − mgμ

∑F = (50 N) − (9 kg) (9.8 m/s²) (0.45)

∑F ≈ 10 N

no sign of dia of fuel cell

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.