Some tropical butterflies can reach speeds of up to 11 m/s. suppose a butterfly flies at a speed of 6.0m/s while another flying insect some distance ahead flies in the same direction with a constant speed. the butterfly then increases its speed at a constant rate of 1.4m/s2 and catches up to the other insect 3.0s later. how far the butterfly travel during the race

24.3 m

Explanation:

Using the equation of motion

where s is the distance, u is initial velocity, t is time and a is acceleration

Substituting u for 6 m/s, t for 3 s, a for 1.4 m/s2 we obtain

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s