Acart loaded with bricks has a total mass of 25.1 kg and is pulled at constant speed by a rope. the rope is inclined at 21.3 ◦ above the horizontal and the cart moves 31 m on a horizontal floor. the coefficient of kinetic sommer (irs359) – wep quiz – craig – (2019-1a ap12) 2 friction between ground and cart is 0.5 . the acceleration of gravity is 9.8 m/s 2 . what is the normal force exerted on the cart by the floor? answer in units of n. 011 (part 2 of 3) 10.0 points how much work is done on the cart by the rope? answer in units of kj. 012 (part 3 of 3) 10.0 points note: the energy change due to friction is a loss of energy. what is the energy change wf due to friction?

2.0 m Since we've been told to ignore friction, then we can also ignore gravity since all it's doing is contributing to the normal force which is only of interest if we're paying attention to friction. So how fast will 13 N of force accelerate 34 kg of mass? Since a newton is kg*m/s^2 and we want to get m/s^2, a simple division should be able to cancel out the kg. So: 13 kg*m/s^2 / 34 kg = 0.382352941 m/s^2 The distance an object moves under constant acceleration is d = 0.5 AT^2 So let's substitute the known values and calculate the distance. d = 0.5 AT^2 d = 0.5 0.382352941 m/s^2 * (3.2 s)^2 d = 0.191176471 m/s^2 * 10.24 s^2 d = 1.957647059 m Rounding to 2 significant figures gives 2.0 meters

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards