Agardener mows a lawn with an old-fashioned push mower. the handle of the mower makes an angle of 320 with the surface of the lawn. if a 249 n force is applied along the handle of the 21-kg mower, what is the normal force exerted by the lawn on the mower?

N = 337.96 N

Explanation:

∅ = 32º

F = 249 N

m = 21 Kg

N = ?

We can apply:

∑ F = 0  (↑)

- Fy - W + N = 0   ⇒    N = Fy + W

⇒  F*Sin ∅ + m*g = N

⇒  N = (249 N*Sin32º) + (21 Kg*9.81 m/s²)

⇒  N = 337.96 N  (↑)

the ima (higher than 1m) will be greater than the ima with the height of 1m.