Aloop of width w 50 cm and height h 10 cm is oriented at angle of 0= 30 degrees with respect to the horizontal. the loop carries a current of 0.8 a. a uniform magnetic field of strength 1.2 t points in the vertical direction. use the right-handed coordinate system given, with +x to the right, +y pointing up, and therefore +z points out of the page. b sin 30 = 0.500 d. с .b 0.866 cos 30° = wi plan view side view (a) find the vector components for the magnetic moment of the loop. express your answer as a decimal number to two significant digits with units. x-component: y-component: (b) if the loop is allowed to rotate, which direction will it turn? (c) calculate the magnitude of the torque on the loop. express your answer as a decimal number to two significant digits with units. (d) what is the difference between the minimum and maximum potential energies of the loop (considering any possible orientation). express your answer as a decimal number to two significant digits with units.

the entire statement is true and correct.  

there's no diagram, nothing is illustrated, and no question is asked.

thermal energy is the answer

do you have a formula possibly

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle  

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.