An 18-cm-long bicycle crank arm, with a pedal at one end, is attached to a 20-cm-diameter sprocket, the toothed disk around which the chain moves. a cyclist riding this bike increases her pedaling rate from 60 rpm to 90 rpm in 10 s. a. what is the tangential acceleration of the pedal?

Explanation:

It is given that,

Length of the bicycle crank arm, l = 18 cm = 0.18 m

Its length will act as the radius of arm.

The diameter of the sprocket, d = 20 cm = 0.2 m

A cyclist riding this bike increases her pedaling rate from 60 rpm to 90 rpm in 10 s.

To find,

The tangential acceleration of the pedal.

Solution,

The rate of change of angular displacement is called angular acceleration of the object. It is given by :

The relationship between the angular acceleration and the tangential acceleration is given by :

Therefore, the tangential acceleration of the pedal is

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

electric field is a function of 1/r^2

yes, the force per unit charge for a point charge is inverse square law.