1.) starting from rest, a car accelerates at 6.52 m/s^2 for 3.80 s. determine the distance traveled by the car during this time.

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could someone me with this like how to work the problem out ? i have been having trouble doing this problem for awhile and still don't understand it. i would be more than grateful for some , !

47.1 m

Explanation:

First, write the information you're given.

v₀ = 0 m/s

a = 6.52 m/s²

t = 3.80 s

Identify the variable you're looking for:

Find: Δx

Next, find the kinematic equation you need to solve.  One trick is to identify which variable you don't have, then find the equation that doesn't use that variable.  In this case, we don't have the final velocity v, so the equation we should use is:

Δx = v₀ t + ½ at²

Plug in the values and solve:

Δx = (0 m/s) (3.80 s) + ½ (6.52 m/s²) (3.80 s)²

Δx = 47.1 m

change tension

molecules are free to separate from each other and will take on the shape of the container. molecules move completely at random and high speeds. they vibrate in a fixed position and do not move around much. molecules expand to the edge of their container.