Two manned satellites approach one another at a relative speed of 0.250 m/s, intending to dock. the first has a mass of 4.00×10^{3} kg, and the second a mass of 7.50×10^{3} kg. if the two satellites collide elastically rather than dock, what is their final relative velocity (in m/s)?

Explanation:

Let are initial speeds of satellite 1 and 2 and are final speeds of satellite 1 and 2 after collision respectively.

It is given that, the relative speed of two manned satellites is 0.25 m/s,

It is mentioned that thy collide elastically rather than dock, the momentum will remain conserved. So,

In elastic collision, the kinetic energy also remains conserved, so

For an elastic collision, the velocity of separation is equal to the velocity of approach such that, e = 1

(given )

So, their final relative velocity is 0.25 m/s. Hence, this is the required solution.

nec chapter 5 contains

c. information on special occupancy areas

nec chapter 6 covers

a. special equipment

which of the following rules contain the words shall or shall not and must be adhered to?

b. mandatory rules

which of the following rules identify actions that are allowed but not required and typically cover options or alternative methods?

c. optional rules

which of the following serves as the introduction to the nec and provides an overview of the book?

a. nec article 90

organizations that test products for safety are

c. nrtls

the nec is published by the

a national fire protection association

the nec is divided into

b. 9 chapters

the nec provides informative annexes for

c. informational materials and examples

two terms from nec article 100 that trainees should become familiar with are

b. labeled and listed

explanation:

the force on the thing and the distance the force moves the thing