Suppose that we replace the aluminum with a mystery metal and repeat the experiment in the video. as in the video, the mass of the metal is the same as that of the water. room temperature is about 20∘c before the start of the experiment. the water heats up to 40∘c, and the mystery metal heats up to 80∘c. compared to that of water, the heat capacity of our mystery metal isa) three times greater. b) one-third as great. c) half as great. d) two times greater. e) the same.

b) one-third as great.

Explanation:

As we know that same heat is supplied in this experiment

so we will have

now we know that both are initially at same temperature

then their final temperatures are

now we have

so we have

so heat capacity of mystery metal is 1/3 times that of water

The heat capacity of our mystery metal is b) one-third as great

The law of conservation of energy can be applied to heat changes, i.e. the heat received / absorbed is the same as the heat released

Q in = Q out

Heat can be calculated using the formula:

the mass of the metal is the same as that of the water

so m water = m metal

the heat energy used to heat water and metals is the same, so

Q water = Q metal

m = metal

w = water

T = the final temperature of the mixture

Tm = metal temperature

Tw = water temperature

so the equation becomes:

the difference between temperature and heat

link

Specific heat

link

relationships among temperature, heat, and thermal energy.

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When heat is added to a substance

link

Keywords: heat, temperature,the heat capacity

area of focus

so easy. just google the electromagnetic waves and it’ll pop up.