Two fun-loving otters are sliding toward each other on a muddy (and hence frictionless) horizontal surface. one of them, of mass 8.00kg , is sliding to the left at 5.50m/s , while the other, of mass 5.75kg , is slipping to the right at 6.00m/s . they hold fast to each other after they collide.

1. find the magnitude of the velocity of these free-spirited otters right after they collide.
2. find the direction of the velocity of these free-spirited otters right after they collide. (right or left)
3. how much mechanical energy dissipates during this play?

Answer

given,

mass of block (m₁)= 8 kg

mass of other block (m₂) = 5.75

velocity of first object (v₁) = 5.5 m/s

velocity of second object (v₂) = 6 m/s

a) total momentum before collision = total momentum after collision

  m₂v₂ - m₁ v₁ = (m₁ + m₂) V

  5.75 x 6 - 8 x 5.5 = (5.75 + 8 ) V

    V = - 0.69 m/s

b) negative sign shows the direction motion of object after collision toward left.

c) Initial kinetic energy

            K_i = 224.5 J

final kinetic energy

                 =

                 =

              K_f = 3.23 J

loss in mechanical energy

 Δ KE = 3.23 - 224.5

Δ KE = -218.1 J

negative sign shows loss of mechanical energy.

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

there are no components of a physical goal mentioned on the list of choices that you've provided.