Amass m of 3.80e-1 kg slides inside a hoop of radius r=1.10 m with negligible friction. when m is at the top, it has a speed of 5.35 m/s. calculate the size of the force with which the m pushes on the hoop when m is at an angle of 34.0°.

N = 26.59 N

Explanation:

given,

mass = 0.38 kg

radius of the hoop = 1.10 m

speed = 5.35 m/s

force = ?

now,

we know that,

N = 26.59 N

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.