Astudent is “accidentally" pushed by mr. m from the top of nhs. the roof of nhs to the ground (by the
cafeteria) is roughly 15.6 meters. if it takes 1.80 seconds to fall, what is the student's acceleration?

downward

Explanation:

The motion of the student is a uniformly accelerated motion, so we can use the suvat equation

where, taking downward as positive direction, we have

s = 15.6 m is the vertical displacement

u = 0 is the initial velocity (we assume the student starts from rest)

t = 1.80 s is the time of the fall

a is the acceleration of the student

By re-arranging the equation and solving for a, we can find the acceleration of the student:

And since the sign is positive, the direction of the acceleration is downward.

a

explanation:

no diagram was provided, but i'm guessing it's the one i've attached to my answer.

here, a mechanical force turns the rod.   this generates an electric current in the coil, which powers the bulb.

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.