Aball is thrown horizontally from a 16 m -high building with a speed of 2.0 m/s .

how far from the base of the building does the ball hit the ground?

3.61 m

Explanation:

First, find how long it takes to land.

Given (in the y direction):

Δy = 16 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

(16 m) = (0 m/s) t + ½ (9.8 m/s²) t²

t = 1.81 s

Given (in the x direction):

v₀ = 2.0 m/s

a = 0 m/s²

t = 1.81 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (2.0 m/s) (1.81 s) + ½ (0 m/s²) (1.81 s)²

Δx = 3.61 m

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

the amount of current in the coil