There are six books in a stack, and each book weighs 5 n. the coefficient of static friction between the books is 0.2. with what horizontal force must one push to start sliding the top five books off the bottom one? a. 1 n c. 3 n b. 5 n d. 7 n

The horizontal force one must push to slide the top five books off the

bottom one is 5 N

We were told  that the 6 books each weigh 5N and we need to slide 5 of

them which is 5×5= 25N

We can then calculate the friction force with the formula below.

F = N μ

where F is frictional force, N is force and  μ is coefficient of static friction

F= (25 N) (0.2)

F= 5 N

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b. 5 N

Explanation:

Each book weighs 5 N.  Therefore, five books weigh 25 N.  The friction force is:

Ff = Fn μ

Ff = (25 N) (0.2)

Ff = 5 N

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever