Aforce, f1, of magnitude 2.0 n and directed due east is exerted on an object. a second force exerted on the object is f2 = 2.0 n, due north. what is the magnitude and direction of a third force, f3, which must be exerted on the object so that the resultant force is zero?

Magnitude of the force is

direction of the force is given as

West of South

Explanation:

As we know that force is a vector quantity and in order to find the resultant of two or more forces we need to add them vectorialy

So here we have

here we know that first force is of magnitude 2 N towards east

second force is also of 2.0 N due North

now from above equation

so magnitude of the force is given as

direction of the force is given as

West of South

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft