Consider the set up in section 3.2. suppose the mass hanging from the side post has a mass of 100g, the side post is located 20cm from the center post, and the mass hanging from the pulley has a weight of 55g. once the 55g mass is removed, what angular velocity ω will the system need for the side post mass to return to the vertical position? consider equation 8.1, and think about the role of the hanging 55g mass.

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.

we need to know the time interval during which the force acts. impulse of force = momentum change

prndulum needs thread, weight clock to time swings