In a "worst-case" design scenario, a 2000-kg elevator with broken cables is falling at 4.00 m/s when it first contacts a cushioning spring at the bottom of the shaft. the spring is supposed to stop the elevator, compressing 2.00 m as it does so. during the motion a safety clamp applies a constant 17000-n frictional force to the elevator. 1) what is the speed of the elevator after it has moved downward 1.00 m from the point where it first contacts a spring? 2) when the elevator is 1.00 m below point where it first contacts a spring, what is its acceleration?

Part a)

Part b)

Explanation:

Part a)

As we know that the elevator is stopped while spring is compressed by x = 2 m

now we will have

Now we have to find the speed when spring is compressed by x = 1

So again by work energy theorem

Part b)

Net force on the elevator while spring is compressed by x = 1

now acceleration is given as

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probably not if net force is zero