An enzyme with a km of 1.2x10-4 m was assayed at an initial sustrate concentration of 0.02 m. by 30 seconds, 2.7 μmoles/liter of product had been produced. how much product will be present at (a) 3 min and (b) 5.3 minutes? (c) what percent of the original substrate is used up at (c) 3 min and (d) 5.3 minutes?

Ater 3 minute

product = Molar

susbtrate = 0.081%

after 5.3 minutes

product =  

susbtrate = 0.01435

Explanation:

Given data:

Sustrate concentration = 0.02 M

Amount of product

Rate = dP/dT = product formed per time

we know rate

hence

now after 3 min = 180 sec

product formed Molar,

% substrate utilised%

after 3.5 minutes = 318

% %

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