The air is less dense at higher elevations, so skydivers reach a high terminal speed. the highest recorded speed for a skydiver was achieved in a jump from a height of 39,000 m. at this elevation, the density of the air is only 4.3% of the surface density of air at 20∘c. estimate the terminal speed of a skydiver at this elevation. suppose the mass of the skydiver is 90 kg and the cross section area of the skydiver is 0.72 m2. you could consider the diver as a cylinder traveling sideways for this problem.

the terminal velocity v_t= 202.96 m/s≅203 m/s

Explanation:

The expression for the terminal velocity

here, C_d is the drag coefficient for the cylinder is 1.15

The surface density of the air at 20°C is

ρ_surface = 1.2041 kg/m^3

the density of air at an altitude of 39000 m

ρ= 4.3/100×39000 = 0.05177 kg/m^3

now substitute these values in equation above

we get

v_t= 202.96 m/s≅203 m/s

the terminal velocity v_t= 202.96 m/s≅203 m/s

the answer is a. the yacht traveled from the dock north to the 200-meter marker in the bay in less than 5 minutes, giving the passengers several more hours to fish.

im doing peak rn so sry if its wrong

f=ma newton

f=100x2.5=250n