Acrate is pushed horizontally by a horizontal force 527.018 n . sliding friction resists the motion, and the kinetic coefficient of friction is 0.17 . the acceleration of gravity is 9.8 m/s 2 . calculate the acceleration of the crate. answer in units of m/s 2 .

m= 10 kg a = 52 m / s²

Explanation:

For this problem we must use Newton's second law, let's apply it to each axis

X axis

      F - fr = ma

The equation for the force of friction is

    -fr = miu N

Axis y

     N- W = 0

     N = mg

Let's replace and calculate laceration

     F - miu (mg) = ma

    a = F / m - mi g

    a = 527.018 / m - 0.17 9.8

We must know the mass of the body suppose m = 10 kg

    a = 527.018 / 10 - 1,666

    a = 52 m / s²

answer; (d) spontaneous processes are characterized by the overall conversion of order to disorder;

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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