In 1994, a tower 22.13 meter tall was built of lego blocks. suppose a block with a mass of 2.00 grams is dropped from the top of this tower. neglecting air resistance, calculate the block's momentum at the instant the block hits the ground.

0.042 kg m/s

Explanation:

In order to solve this, we need to find the final velocity of the block at the moment it its the ground.

The motion of the block is a free fall motion, so it is a uniform accelerated motion, so we can use the following suvat equation:

where:

v is the final velocity

u = 0 is the initial velocity (it starts from rest)

is the acceleration of gravity (we chose downward as positive direction)

s = 22.13 m is the displacement

Solving for v,

Now we can find the final momentum of the block, using the equation:

p = mv

where

m = 2.0 g = 0.002 kg is the mass of the block

Substituting,

float.

archimedes' principle

denser than water sinks in water.

denser than mercury would sink in it

0.93xc=0.93x3x10^8m/s

2.54cm is 1 inch

360seconds i 1 hr