1a football player runs directly down the field for 35 m before turning to the right at
an angle of 25' from his original direction and running an additional 15 m before
getting tackled. what is the magnitude and direction of the runner's total
displacement?

The magnitude of displacement is 56.54 m

The direction of the displacement is along the line joining the two vectors.

Explanation:

The resultant displacement is always the line joining the initial and final position of the vectors.

As in figure,

              the vector AB = 35 m

              the vector BC =  15 m

              the angle between AB and AC = 25'  (minutes)

              the resultant vector AC = ?

The resultant vector is given by the formula

             AC² = AB² + BC² + 2 AB BC Cos θ

Substituting the values in the equations,

             AC²  = 35² + 15² + 2 x 35 x 15 x Cos 25'

                      = 56.54

Therefore, the magnitude of displacement is 56.54 m

The direction of the displacement is along the line joining the two vectors.

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