Aparallel plate capacitor with plate separation of 4.0 cm has a plate area of 6.0×10-2 m2. what is the capacitance of this capacitor if a dielectric material with a dielectric constant of 2.4 is placed between the plates?

32pF

Explanation:

The capacitance of a parallel plate capacitor is given by the following equation:

Where:

is the electric constant when the dielectric material is vacuum

is the area of each plate

is the separation distance between both plates

This is the capacitance when the dielectric is vacuum.

Now, we can calculate the capacitance , when we have a dielectric material with a dielectric constant :

Finally:

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explanation:

think its the third option