To understand the meaning and possible applications of the work-energy theorem.

in this problem, you will use your prior knowledge to derive one of the most important relationships in mechanics: the work-energy theorem. we will start with a special case: a particle of mass m moving in the x direction at constant acceleration a . during a certain interval of time, the particle accelerates from vinitial to vfinal , undergoing displacement s given by s=xfinal−xinitial

find the acceleration a of the particle.

100 pounds is 100 pounds no matter the object or item being weighed

stands for electromotive force and it is measured in volts. despite its name, it is not actually the force in the sense of being a "pushing" or "pulling" (not measured in newtons).an equation that relates emf,  ℰ,  to a battery's terminal voltage, v, current, i, and internal resistance, r, is    ℰ = v + irin this case, the emf can be interpreted as a voltage—a difference in electric potential.i would not say that it would be considered an energy. if emf can be defined as the energy/work per a unit charge from a battery or other electric source, then it is not strictly energy.