Aforce f = 73.6 n i + 60.0 n j is applied to a 12.3-kg cart on a level frictionless floor [x-horizontal, y-vertical directions]. the cart starts from rest and moves horizontally along the floor due to this force. what is the cart's instantaneous velocity (m/s) when it is moved by 8.61 m?

160 Joules

  For this problem, we can ignore the vertical component of the applied force and focus on only the horizontal component of 80 N and since work is defined as force over distance, let's multiply the force by the distance: 80 N * 2.0 m = 160 Nm = 160 kg*m^2/s^2 = 160 Joules.

  So the cart has a final kinetic energy of 160 Joules.

Explanation:

explanation:

0.863333

86%

hope this