An alpha particle (a he nucleus, containing two protons and two neutrons and having a mass of 6.6. an alpha particle (a he nucleus, containing two protons and two neutrons and having a mass of 6.64×10−27 kg ) traveling horizontally at 36.6 km/s enters a uniform, vertical, 1.10 t magnetic field.
(a)- what is the diameter of the path followed by this alpha particle? express your answer in millimeters to three significant figures.
(b)- what effect does the magnetic field have on the speed of the particle?
(c)- what is the magnitude of the acceleration of the alpha particle while it is in the magnetic field? express your answer in meters per second to three significant figures.
(d)- what is the direction of the acceleration of the alpha particle while it is in the magnetic field?
(e)- explain why the speed of the particle does not change even though an unbalanced external force acts on it.

Ibelieve your answer is b.hope this : )

That would be the corect answer hope this

Answer: a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same sign as the  -4.0  µc charge.======electricstatic force between two point charges  is given by    where k is coulomb's constant,  8.99×10⁹  n·m²/c², q₁ and q₂ are the point charges, and r is the distance between the two point charges.assign positive to q₁let q₁ =  6.0 µc, q₂ = -4.0  µc, q₀ represent the charge at the origin, and q₃ represent this new charge to place.the charge at the origin q₀ would experience the following force f₀₁ from q₁, with r = 6.0 m (note that 1  µc = 10⁻⁶ c)    the force from q₂    the force from q₃    the net force on the origin charge, q₀, has to be zero for no electrostatic forcehaving an equation where k and q₀ can be divided out of the equation will allow us to solve for q₃    isolating:     a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same as the  -4.0  µc charge