Mary applies a force of 79 n to push a box with an acceleration of 0.45 m/s2. when she increases the pushing force to 84 n, the box's acceleration changes to 0.61 m/s2. there is a constant friction force present between the floor and the box. slader

The mass of the box, m = 31.25 kg

Explanation:

It is given that,

Condition (1)

Force applied by Mary, F₁ = 79 N

Acceleration of the box,

Condition (2) :

Force applied by Mary, F₂ = 84 N

Acceleration of the box,

Let m is the mass of the box. It is assumed to find the mass of the box. The resultant forces acting on the box in condition (1) are :

...........(1)

f is the force of friction acting between the floor and the box.

The resultant forces acting on the box in condition (2) are :

..........(2)

On solving equation (1) and (2) we get :

f = 64.938 N

m = 31.25 kg

So, the mass of the box is 31.25 kg. Hence, this is the required solution.

grav force prop 1/r squared 2r all squared is 4rsquared 1/4rsquared quartered