Atrain moving with a velocity of 42.9 km/hour north, increases its speed with a uniform acceleration of 0.250 m/s^2 north until it reaches a velocity of 160.0 km/hour north. what distance did the train travel while it was increasing its velocity, in units of meters? give the answer as a positive number

3658.24m

Explanation:

Hello!

the first thing that we must be clear about is that the train moves with constant acceleration

A body that moves with constant acceleration means that it moves in "a uniformly accelerated motion", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.

When performing a mathematical demonstration, it is found that the equations that define this movement are as follows.

Vf = final speed =160km/h=44.4m/s

Vo = Initial speed =42.9km/h=11.92m/s

A = acceleration =0.25m/s^2

X = displacement

solving

the distance traveled by the train is 3658.24m

that tool is called an altimeter which measures your altitude which can be used to tell which atmosphere you are currently in, including the stratosphere.

hope this ! : )