Physics, 17.10.2019 23:30 ryan23allen

Astudent throws a water balloon with speed v0 from a height h = 1.82 m at an angle θ = 29° above the horizontal toward a target on the ground. the target is located a horizontal distance d = 7.5 m from the student’s feet. assume that the balloon moves without air resistance. use a cartesian coordinate system with the origin at the balloon's initial position. determine the magnitude of the balloon's initial velocity, v0, in meters per second.

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Answer from: Flaka2809

The magnitude of the balloon's initial velocity is 7.80 m/s

The given parameter

height from which the balloon was thrown, h = 1.82 mthe initial velocity of the balloon, = v₀ the angle of projection, θ = 29⁰the horizontal distance of the balloon, x = 7.5 m

To find:

the magnitude of the balloon's initial velocity

The vertical component of the velocity is calculated as;

$v_y = v_0\times sin(\theta)\\\\v_y = v_0 \times sin(29)\\\\v_y = 0.4848v_0$

The horizontal component of the velocity is given as;

$v_x = v_0\times cos(\theta)\\\\v_x = v_0 \times cos(29)\\\\v_x = 0.8746v_0$

The horizontal distance or range of the projectile is given as;

$X = v_xt \\\\7.5 = 0.8746v_0t\\\\v_0t = \frac{7.5}{0.8746} \\\\v_ot = 8.575 \$

The change in vertical height of the balloon is given as;

$\Delta h = v_yt - \frac{1}{2}gt^2\\\\h_2-h_1 = v_yt - \frac{1}{2}gt^2$

assume the balloon falls to zero position

$0-1.82 = v_yt - \frac{1}{2} gt^2\\\\-1.82 = v_yt - \frac{1}{2} gt^2\\\\-1.82 = 0.4848v_0t - \frac{1}{2} (9.8)t^2\\\\-1.82 = 0.4848(8.575) - 4.9t^2\\\\4.9t^2 = 4.157 + 1.82\\\\4.9t^2 = 5.977\\\\t^2 = \frac{5.977}{4.9} \\\\t^2 = 1.2198\\\\t = \sqrt{1.2198} \\\\t = 1.1 \ s$

The magnitude of initial velocity of the balloon is calculated as;

$v_0t = 8.575\\\\1.1v_0 = 8.575\\\\v_0 = \frac{8.575}{1.1} \\\\v_0 = 7.80 \ m/s$

Thus, the magnitude of the balloon's initial velocity is 7.80 m/s

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Answer from: bbyggigi94041

v_o = 7.76 m/s

Explanation:

As we projected the balloon at speed vo at an angle of 29 degree

so the two component of velocity is given as

v_x = v_ocos29 = 0.875 v_o

v_y = v_o sin29 = 0.485 v_o

now we know that in x direction we have

d = v_x t

7.5 = 0.875 v_o t

v_o t = 8.57

in y direction we have

$- 1.82 = (0.485 v_o) t - \frac{1}{2}gt^2$

-1.82 = 0.485(8.57) - 4.9 t^2

t = 1.1 s

now we have

v_o = 7.76 m/s

Answer from: Quest

quantum mechanics or quantum physics is physics of very small objects (particles) and physical entities.

quantum physics has some parallels to our macro world and some pretty unique ideas which theoretically and mathematically proven to be true even though we will never be able to access them because of our size.

there are many types of particles: subatomic, elementary etc.

subatomic means they are smaller than atom, elementary means they are at the very basis of everything.

subatomic particles are for eg. protons, neutrons but not electrons.

elementary particles are categorised into 3 groups by what they do.

these 3 groups are quarks, leptons and bosons.

light for example is a particle more precisely a photon a part of leptons.

proton (subatomic particle) is made out of 2 up quarks and 1 down quark each of these has a fractional charge like $\frac{1}{3}$ . (i crazy)

most famous scientist who contributed to this physics are:

max planckalbert einsteinerwin schrödingermany

the topic itself us understand a lot and will probably be vastly used in the future (quantum computers, understanding the big bang,

we also must not forget quantum effects like:

superposition (where 1 thing can be this and that at the same time),entanglement (where two particles are seemingly connected by some sort of unknown (or known) force, energy, matter (i know all that can be the same at least it was at the beginning)

and there is more. but probably too much for this answer to be consistent due to my average understanding of this topic.

hope this you understand quantum mechanics a little more. i'm not an expert in the topic (so don't be like wth if you are an expert) but i'm very interested in it.

anyways quantum physics is a very hard topic (harder than physics (perhaps)) therefore searching for every information there is about it and learning it is unfortunately impossible (you can only specialise into 1 - 3 things or more (perhaps

have fun and i wish you luck!

r3t40

Answer from: Quest

photocells convert light energy to electricity

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